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Electric field inside charged conducting sphere?

  1. Apr 10, 2015 #1
    i know it s zero because of the electrostatic equilibrium, but in terms of point charges : from the charge distribution on the sphere surface if we consider 2 point charges opposite to each other in direction : it s logical that at the point in the mid distance between them the electric field will be zero : (kq1/r1^2)=(kq2/r2^2) where q1=q2 and r1=r2, but if we consider a point closer to a point charge than the other charge : q1=q2 also but r1 not equal r2, therefore it s logical that there will be net field at this point, but there is no field at any point inside the sphere, so what is the solution of this contradictory ???
     
  2. jcsd
  3. Apr 10, 2015 #2

    robphy

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    It's not just about those two point charges.
    A brute-force calculation might help... after which one might have more appreciation for Gauss' Law.
     
  4. Apr 10, 2015 #3
    Very very crudely (I hate to do this) it's because for a point off-centre there are more point charges on the sphere further away than there are closer - the effect balances out exactly when you add them all up. Surely any E&M textbook shows how to do the integration.
     
  5. Apr 10, 2015 #4
    nailed it ! thanks man ...
     
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