Electrolysis calcul with faraday

AI Thread Summary
The discussion revolves around calculating the electricity required for electrolysis over a large area of seawater, specifically a surface of 100 feet wide and half a mile long. Participants note that significant current and electrode area are necessary for effective electrolysis, emphasizing that the distance between electrodes is less critical than the potential difference. A specific energy requirement of 5580 MegaJoules for 1000 kg of chlorine is mentioned as a reference. The original poster expresses uncertainty about the exercise's formulation and plans to consult their professor for clarification. Overall, the conversation highlights the complexities of electrolysis in seawater and the practical considerations involved.
cancerman
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Hello felow's my boy of 15 years old asked a question about an exercice at college, he asked me how much electricity it would take to generate electrolysis on a sea surface of 100 feet wide and half a mile long.

I told him (jocking) you may use some kind of nuclear facilities

I thought using Faraday loies could help me but I'm buging, thank you advice in any case

matt's
 
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Hello and :welcome:

First of all you need a lot of cable :smile: .

But the electrochemical processes do not really depend on the distance between the electrodes: the sea can be supposed to be at zero potential and the processes are driven by potential difference.

If you want to electrolyze a substantial amount of sea water, you need a lot of current and thereby a lot of electrode area.

And the fish won't be all that happy with the chemical products !
 
Hello BvU

first thank you for your answer it's nice :) i will tell him about the electrodes first.

so for your what kind of energy are we talking ?maping 100 feet wide and half a mile long of multiple electrode. Fish may won't be all that happy you right , a good way of fishing lol
 
Problem example 2 in http://www.chem1.com/acad/webtext/elchem/ec8.html works it out: 5580 MegaJoule for 1000 kg of Cl2.
The 100 ft and the half mile don't really come into it - except that you need a lot of area and small distance between cathode and anode to get down to the cells operating at 2 Volt.

So what's the problem formulation for this exercise at college ? Sounds ambitious !
 
example 2 look good thank you for the link BvU, yes i think the formulation is wrong somewhere, i will ask the professor

thank you
 

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