Electromagnetic boundary conditions for symmetric model

  • #1
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I stumbled upon this article: http://www.comsol.com/blogs/exploiting-symmetry-simplify-magnetic-field-modeling/

Since the article does not contain any mathematical formulations, I was wondering how the boundary conditions can be expressed in terms of magnetic vector potential.

From what I have gathered, the Perfect Magnetic Conductor boundary condition corresponds to a Zero Neumann boundary condition, where the normal derivative of the magnetic vector potential is set to zero at the boundary:

[tex]{\mathbf{\hat{n}} } \cdot \dfrac{\partial \mathbf{A}}{\partial \mathbf r} = 0[/tex]

From the above, how can one prove that this forces the magnetic flux density vector to cut the boundary at right angle?

Also, I am having trouble figuring out what the Magnetic Insulation boundary condition corresponds to. Is it a Dirichlet boundary condition?

If yes, is it [tex]{\mathbf{\hat{n}} \cdot {\mathbf A}} = 0 [/tex], or just [tex]{\mathbf A} = 0 [/tex]

If it is the former, I can see how the magnetic flux density is zero in the normal direction to the boundary and non-zero in the tangential direction.

Thanks in advance for your time.
 

Answers and Replies

  • #2
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Anyone?
 

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