Atria said:I have two wires in parallel at a distance r apart. They are unequal in length. The current carrying primary generates a magnetic field B at distance r. What is the area related to the secondary through which B passes? Is it correct to assume the thickness times the length of the secondary? All I want to do is calculate the value of E, induced in the secondary.
Atria said:The secondary is shorter than the primary
Electromagnetic induction of two wires is a phenomenon where a change in the magnetic field of one wire induces an electric current in the other wire. This is due to the interaction between the magnetic fields created by the flow of electric current in the wires.
When there is a change in the magnetic field of one wire, it creates a changing magnetic flux. This changing magnetic flux then induces an electric current in the other wire, as described by Faraday's Law of Induction.
Electromagnetic induction of two wires has various practical applications, such as in transformers, generators, and electric motors. It is also used in wireless charging technology and in induction cooktops.
The strength of the induced current in the second wire is inversely proportional to the distance between the two wires. This means that the closer the wires are, the stronger the induced current will be.
The amount of induced current depends on the rate of change of the magnetic field, the distance between the wires, the material and thickness of the wires, and the orientation of the wires with respect to each other and the changing magnetic field.