Electromagnetics: Moving loop in a static magnetic field

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SUMMARY

The discussion focuses on calculating the current in a conducting square loop moving in a static magnetic field, defined by a magnetic flux density of B=Bo ax Wb/m². The relevant equations include Ohm's law (I=V/R) and the electromotive force (Vemf=u × B × dl). The initial attempt at a solution contained errors in vector notation and the application of differential quantities. Correcting these mistakes is essential for accurately determining the direction and magnitude of the current in the loop.

PREREQUISITES
  • Understanding of electromagnetism principles, specifically Faraday's law of induction.
  • Familiarity with vector calculus, particularly cross products.
  • Knowledge of Ohm's law and electrical resistance concepts.
  • Basic understanding of Lenz's law and its application in electromagnetic systems.
NEXT STEPS
  • Review vector calculus, focusing on cross products and their applications in electromagnetism.
  • Study Faraday's law of induction in detail to understand the relationship between magnetic fields and induced currents.
  • Learn about Lenz's law and how it determines the direction of induced current in conductive materials.
  • Practice solving problems involving moving conductors in magnetic fields to reinforce understanding of the concepts.
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Students studying electromagnetism, physics educators, and anyone involved in electrical engineering or related fields seeking to understand the dynamics of conductors in magnetic fields.

JasonHathaway
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Homework Statement


A conducting square loop (L × L) moving with velocity vo ay m/s where the magnetic flux density is B=Bo ax Wb/m2 in 0 < y < 2L, and is equal to zero when 0 > y and y > L. Determine the current in the loop and plot its magnitude as a function in the loop's position in the y-axis. Assume the loop's front at y=0 and t=0 (time), and its resistance is R Ω.
5MKxNMk.png


Homework Equations


I=V/R (Ohm's law)
Vemf=u × B × dl (× refers to cross product, u is the velocity)

The Attempt at a Solution


Vemf=- vo B l V
I=Vemf/R = ( - vo B l )/ R A

wtAqScx.png
I don't know whether I am doing OK or not. I feel like I've missed up with dl. Can anyone clarify?
 
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JasonHathaway said:

Homework Equations


I=V/R (Ohm's law)
Vemf=u × B × dl (× refers to cross product, u is the velocity)
This formula is wrong, in fact, it's not a formula at all since you can't write "a x b x c". Plus, you're equating a differential quantity with a finite quantity. You need to be more careful with your vector math. But express V as a differential and fix your "u × B × dl" term, and you're there.
As for your "Vemf=- vo B l V", that is OK in magnitude but you need to get the vector formula right to determine the direction of the current. Or use Lenz's law.
And BTW V is not a vector.
 

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