Electron Accleration Calculation | Homework Solutions

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SUMMARY

The discussion focuses on calculating the acceleration of an electron in an electric tube, given its mass of 9.1 x 10-31 kg and a net force of 8.0 x 1015 N over a distance of 2.0 cm. The acceleration is determined using the formula a = Fnet/m, resulting in an acceleration of approximately 8.79 x 1046 m/s2. For part B, the discussion suggests using the 1-D kinematics equation to find the final velocity of the electron after traveling 2.0 cm, assuming it starts from rest.

PREREQUISITES
  • Understanding of Newton's second law (Fnet = ma)
  • Basic knowledge of kinematics equations
  • Familiarity with unit conversions (e.g., cm to meters)
  • Concept of force and mass in physics
NEXT STEPS
  • Research the 1-D kinematics equation: v2 = u2 + 2as
  • Explore the implications of relativistic effects on electron acceleration
  • Study the relationship between force, mass, and acceleration in different contexts
  • Investigate practical applications of electron acceleration in electric fields
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Students studying physics, particularly those focusing on mechanics and electromagnetism, as well as educators looking for homework solutions related to electron dynamics.

soulja101
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Homework Statement


In an electric tube, an electron of mass 9.1*10 to the power of negative 31 kg experiences a net force of magnitude of 8.0*10 to the power of 15 over a distance of 2.0cm.

A)calculate the magnitude of the electron's acccleration
B)assuming it started from rest, how fast would the electron be moving at the end of 2.0cm motion.

Homework Equations


Fnet=ma


The Attempt at a Solution


a=?
m=9.1*10 to the power of negative 31
d=2.0cm
Fnet-ma
a=fnet/m
=8.0*10 to the power of 15/.1*10 to the power of negative 31 kg

I didnt get how to question B)
 
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soulja101 said:

Homework Statement


In an electric tube, an electron of mass 9.1*10 to the power of negative 31 kg experiences a net force of magnitude of 8.0*10 to the power of 15 over a distance of 2.0cm.

A)calculate the magnitude of the electron's acccleration
B)assuming it started from rest, how fast would the electron be moving at the end of 2.0cm motion.

Homework Equations


Fnet=ma


The Attempt at a Solution


a=?
m=9.1*10 to the power of negative 31
d=2.0cm
Fnet-ma
a=fnet/m
=8.0*10 to the power of 15/.1*10 to the power of negative 31 kg

I didnt get how to question B)

Look here

https://www.physicsforums.com/showthread.php?t=110015

to find the 1-D kinematics equation that relates the change in velocity to a known acceleration over a known distance.
 

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