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## Homework Statement

Hello! I am doing some calculations with electron capture for the reaction

[tex] \stackrel{196}{79}Au\stackrel{EC}{\rightarrow}\stackrel{196}{78}Pt[/tex]

The Q-value for the reaction is

[tex] Q=[m(\stackrel{196}{79}Au-\stackrel{196}{78}Pt]c^2-B_{n}[/tex] where [tex] B_{n}[/tex] stands for electron's binding energy.

We calculated this value and got

[tex] Q=1.429 MeV[/tex] but I do not know how to find the value of [tex] B_{n}[/tex] the teacher just wrote value for [tex] B_{n}=0.08MeV[/tex]

Can someone please explain to get this value?