Electron diffraction - effect of electron wavelength

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SUMMARY

The discussion centers on the relationship between electron wavelength and diffraction patterns, specifically in the context of electron diffraction. Increasing the electron wavelength results in larger diffraction rings, as described by Bragg's law: n.lambda = 2.d.sin theta. This law illustrates that as the wavelength (lambda) increases, the diffraction angle (theta) also changes, leading to a more pronounced diffraction effect. Conversely, decreasing the wavelength leads to smaller rings due to reduced diffraction.

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  • Understanding of Bragg's law in crystallography
  • Knowledge of electron diffraction principles
  • Familiarity with atomic spacing in materials like graphite
  • Basic concepts of wave-particle duality in quantum mechanics
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Molly1235
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Hello, I know how electron diffraction works, and that if you decrease the wavelength of the electrons less diffraction occurs, so the rings are smaller, however was wondering what happens if the wavelength is increased? Is it just the opposite? More diffraction so larger rings?

I was also thinking that perhaps less diffraction happens if you increase the wavelength as well as if you decrease it, as the wavelength is getting further away from the atomic spacing of the graphite or whatever is being used.

Both made sense in my head so I wonder if anyone can help?

Thanks!
Molly :)
 
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Hello,

The effect of the electron wavelength on the diffraction angles is described by Bragg's law:

n.lambda = 2.d.sin theta

with n the order of the diffraction, lambda the wavelength, d the distance of the diffraction grating (i.e. the distance between crystal planes) and theta the diffraction angle. With this law, you can see immediately the effect of a change in wavelength.
 

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