Electron Diffraction: Isolating Particles

  • Thread starter Thread starter kooombaya
  • Start date Start date
  • Tags Tags
    Particles
kooombaya
Messages
36
Reaction score
0
Today in class we learned about electron diffraction and the wave-particle duality. Fascinating stuff (from what I understood) but I was wondering, how do scientists isolate the electrons to be used in the experiment? I know you can do neutron scattering as well, how would you isolate neutrons?? And protons??

For electrons I know you can use the free electrons not tightly bonded and form a potential to get them going.
 
Physics news on Phys.org
kooombaya said:
Today in class we learned about electron diffraction and the wave-particle duality. Fascinating stuff (from what I understood) but I was wondering, how do scientists isolate the electrons to be used in the experiment? I know you can do neutron scattering as well, how would you isolate neutrons?? And protons??

For electrons I know you can use the free electrons not tightly bonded and form a potential to get them going.

Most electron sources used for such studies come from "simple" electron gun that produces electrons via thermionic emission. This is identical to the ones used in cathode ray tubes, i.e. old TV sets.

Neutron sources are an entirely different beasts. Neutron scattering experiments are typically done at experimental nuclear reactors, or at spallation sources.

Zz.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top