Electron in an electirc field.

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SUMMARY

The discussion focuses on calculating the potential difference required to accelerate an electron to a speed of 1.80×106 m/s. The relevant equation used is E = 0.5 m v2 = eV, where E is energy, m is mass, v is velocity, e is the charge of the electron, and V is the potential difference. The user initially miscalculated by not converting energy from Joules to Volts, which led to incorrect results. Correct application of the formula and unit conversion is essential for accurate calculations.

PREREQUISITES
  • Understanding of classical mechanics, specifically kinetic energy calculations.
  • Familiarity with the charge of an electron (approximately 1.602 x 10-19 Coulombs).
  • Basic knowledge of electric potential and voltage.
  • Ability to perform unit conversions between Joules and Volts.
NEXT STEPS
  • Review the concept of kinetic energy and its relation to electric potential energy.
  • Learn about the charge of subatomic particles, specifically electrons.
  • Study the principles of electric fields and their effects on charged particles.
  • Practice unit conversions between Joules and Volts in various physics problems.
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Students studying physics, particularly those focusing on electromagnetism and particle dynamics, as well as educators looking for examples of energy conversion in electric fields.

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Homework Statement



Across what potential difference does an electron have to be accelerated in order to reach speed v=1.80×106 m/s?

Homework Equations



I checked to see if relativity was important and it was not
E=.5 m v^2=eV


The Attempt at a Solution




I don't know if I am mistaken in what I am trying to find but I thought the potential difference in this case was .5mv^2 But when I plug in 9.109x10^-31 kg in for the mass and 1.8x10^6 m.s for the velocity I don't get the right answer. I do not know what I am doing wrong.
 
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I figured out what I was doing wrong. It was in Joules and I needed to convert to Volts.
 

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