Electron Motion in Charged Plate Region: Time, Distance, and Velocity Components

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An electron with an initial horizontal velocity of 3.16 × 10^9 cm/s enters a region between charged plates, traveling a horizontal distance of 2.42 cm while experiencing a downward acceleration of 2.73 × 10^17 cm/s². The equation s = ut + 0.5at² is used to find the time required for the electron to travel this distance, yielding a time of approximately 7.42 seconds. The discussion highlights confusion regarding the combination of horizontal and vertical motion in calculations. Participants suggest separating the equations for horizontal and vertical components to solve for the vertical distance and velocity components. Clarifying these calculations is essential for completing the problem accurately.
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Homework Statement


An electron, with an initial horizontal velocity of magnitude 3.16 × 109 cm/s, travels into the region between two horizontal metal plates that are electrically charged. In that region, it travels a horizontal distance of 2.42 cm and has a constant downward acceleration of magnitude 2.73 × 1017 cm/s2 due to the charged plates. Find (a) the time required by the electron to travel the 2.42 cm and (b) the vertical distance it travels during that time. Also find the magnitudes of the (c) horizontal and (d) vertical velocity components of the electron as it emerges.

Homework Equations


s = ut +0.5at^2

The Attempt at a Solution


s = ut + 0.5at^2
2.42 = 3.16x10^9t +1.365x10^17t^2
t = 7.42

I'm not sure whether what i did was correct and also don't know how to do parts b, c and d.
 
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You have combined the two different directions for some reason into the same equation. Try to separate the equation for the two directions.
 
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