frandango said:
It's not really as complicated as people are making out
No, it's actually a lot
more complicated. There's a whole big field dedicated to trying to find better ways of solving the quantum many-body problem. I've got a half-dozen grad-level textbooks in my office that contain nothing other than various methods and approximations to calculate it. It
is complicated.
I have only just joined this forum and am a bit surprised how snide a lot of these comments are!
Personally, I found the rudest comment to be the one an explanation because they think "books are boring" and can't be bothered to actually do any work. Nobody ever learned physics without work.
(But if you think that's okay, would you please pay my rent for me? I can't be bothered to go to work. It tires me. Could someone just do the work and give me a 10-minute rundown of what's going on at the office?)
What we use for multi-electron atoms is to work with a 'fiddle factor' that uses perturbation theory. As you say, we must take into account the electron-electron repulsion. We work out what sort of contribution that would make, and then factor it into the energy calculations.
Who uses first-order perturbation theory for atomic/molecular calculations other than as a textbook example?
For the ground state of Helium you end up with an approximate energy of -74.8eV which is close to the measured value (but the integrals to work this out are quite nasty).
That's, -2.74 Hartrees, the best value you can get with a wavefunction consisting of two hydrogenic wavefunctions. It's not at all near the measured value, which is -2.90372. It's not accurate enough for spectrocopy, it's not accurate enough for chemistry. And historically, it was not accurate enough to be able to say that the 'new' quantum theory worked for polyelectronic molecules. That was settled by Egil Hylleraas in 1929, by a direct variational calculation with the result -2.9032 Hartrees
For lots of larger atoms, though, we can just use the Hydrogen model because the nucleus is shielded by lower-level electrons and we can pretend that there's only a single electron that's used for calculations.
When is this used, and by whom?
So even though Bohr's model isn't correct, it still "works" for many cases.
No, it doesn't work in many cases at all. There aren't very many single-atom, single-electron systems. And you wouldn't use the Bohr model even then, because there's a well-known 'exact' solution to the Schrödinger equation for them.