Electronics - Designing a ciruit

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To design a circuit with a 15V power supply and a 5 kilo ohm load that allows for a current of approximately 2mA, two resistors totaling 2.5 kilo ohms should be placed in series with the load. The load represents a device that consumes electrical energy, such as a speaker or lightbulb, and its resistance must be considered in the circuit design. By applying Ohm's law (I = V/R), the configuration will yield the desired current. The proposed solution effectively meets the requirements of the problem. Understanding the role of the load is crucial for accurate circuit design.
kel
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Homework Statement



Given an ideal power supply of 15 V and a load of 5 kilo ohms, design a circuit using 2 resistors in which the current flowing through the load is close to 2mA

Homework Equations



None given (I'm assuming V=IR)


The Attempt at a Solution




I'm a bit confused with this one, I understand that maybe I could have 2 resistors of 3.75 kilo ohms each to cause the current to me 2mA, but I'm unsure of what role the '5 kilo ohm load' has.

Can anyone explain to me what this load is and what role it plays? I can't see it being internal resistance due to the power supply being 'ideal'.

Thanks
Kel
 
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A load could be a bunch of things, say a speaker or a lightbulb or an appliance. They consume electrical energy and can dissipate it as sound, light or heat...whatever the case may be. I believe you need to consider the resistance of the load in your design.
 
So basically I could just have 2 resistors in series with a total resistance of 2.5 kilo ohms and the 5 k'ohm load.

Thus, using I = v/R I'd get the 2mA that is expected!

Does that make sense??
 
Thread moved from Advanced Physics to Intro Physics.

kel, yes your answer is correct. By placing the 2.5 kOhms in series with the 5.0 kOhms, that will give you a 2mA current supplied by the 15V power supply.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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