MHB Electronics Engineering: Determine Voltage in Circuit w/ Practical Model

AI Thread Summary
The discussion focuses on determining the voltage at various points in a circuit with respect to ground, using a practical model. It is established that point A has a voltage of +25 V due to a voltage source. Point B's voltage is calculated to be 24.3 V, accounting for a 0.7 V drop across a diode. Participants express confusion about calculating the voltage at point C and seek guidance on determining the voltage at point D as well. The conversation highlights the importance of understanding voltage drops in circuits with diodes.
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Determine the voltage with respect to the ground at each point in figure. Assume the practical model.

View attachment 1846

guys please help me solve this circuit. anybody in electronics engineering help.
 

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paulmdrdo said:
Determine the voltage with respect to the ground at each point in figure. Assume the practical model.

View attachment 1846

guys please help me solve this circuit. anybody in electronics engineering help.

Both the diodes are in on state and in this condition the voltage drop on them is $V_{d} \sim .7 V$ no matter which is the current... Kind regards $\chi$ $\sigma$
 
I don't understand. the question is asking for the voltage with respect to the ground.:confused:
 
paulmdrdo said:
I don't understand. the question is asking for the voltage with respect to the ground.:confused:

Let's start with point A.
There is a voltage source between ground and point A.
Its voltage is 25 V.
Therefore the voltage at point A is +25 V.
 
point B is 24.3v. because the voltage drop across the diode is 0.7v so 25-0.7v=24.3 v

but i don't know how to determine the voltage at point c.
 
paulmdrdo said:
point B is 24.3v. because the voltage drop across the diode is 0.7v so 25-0.7v=24.3 v

Good!

but i don't know how to determine the voltage at point c.

Let's do point D first then...
 
but how?:confused:
 
paulmdrdo said:
but how?:confused:

There is a voltage source between ground and point D that determines its voltage.
 

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