Electrostatic Field Lab Question

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SUMMARY

The discussion focuses on calculating the maximum electric field between two conductors connected to a 6V DC battery. The user seeks to apply Coulomb's law to determine the electric field using voltage and distance, despite not having the charge values in coulombs. The relationship between electric field and voltage is clarified, emphasizing that the electric field (E) can be expressed as E = -ΔV/Δs, where ΔV is the voltage difference and Δs is the distance between the conductors.

PREREQUISITES
  • Understanding of electric fields and voltage concepts
  • Familiarity with Coulomb's law
  • Knowledge of multimeter usage for measuring voltage
  • Basic calculus for understanding gradients and integrals
NEXT STEPS
  • Study the application of Coulomb's law in electric field calculations
  • Learn about the relationship between voltage and electric field strength
  • Explore the use of multimeters in measuring electric fields
  • Investigate the concept of electric potential and its mathematical representation
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Students in physics, electrical engineering majors, and anyone interested in understanding electric fields and their calculations in practical applications.

QuarkCharmer
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Homework Statement


Based on Volts and distance, calculate the max Electric Field between lines.

Homework Equations



The Attempt at a Solution


We basically connected a 6Vdc battery to a plate containing two conductors and use a multimeter to plot the lines of flux of the field. To find the max magnitude of the electric field I would apply coulombs law two a point between the two conductors with charges 6 and -6 Volts. However, I don't know how to do that using volts and distance, since I an not given the charges in coulombs. If the electric field can also be defined as Volts/Meter, how would one go about doing that?
 
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Generally we have that ##\mathbf{E}=-\nabla V##, which can also be written as ##\int \mathbf{E} \cdot d{s} = -\Delta V## along some path.

For a small step in the direction of the electric field this means: ##E = -{\Delta V \over \Delta s}##.
 

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