The discussion centers on electrostatic shielding within a cavity, specifically addressing the behavior of electric fields in the presence of a conductor with an open lid. It is established that the electric field in the marked area inside the conductor will be zero, as electric fields cancel out within conductors. The conversation references the principles of Faraday cages, noting that while a closed Faraday cage effectively shields against external electric fields, an open conductor may still allow some field interaction, particularly at the edges. However, the net electric field remains negligible as one approaches the bottom of the cavity.
PREREQUISITESThis discussion is beneficial for physicists, electrical engineers, and students studying electrostatics, particularly those interested in the practical applications of electrostatic shielding and electric field behavior in conductors.
Why??TESL@ said:It would be zero.
File clean: https://www.virustotal.com/en/file/...e321fae9d85b910a9c5f16c3/analysis/1418672218/
@bhishek said:Why??
But the Faraday's cage is a closed one. Will the same principal be applicable to an open lid conductor also??TESL@ said:Electric fields cancel out inside of a conductor.
This is a good visual: http://en.wikipedia.org/wiki/Faraday_cage#mediaviewer/File:Faraday_cage.gif
Thank you,for explaining.TESL@ said:Not that far. Think of a hollow semi-sphere and a small sphere on its center, connected to it. When you apply an electric field in center to semi-sphere direction, there will be perpendicular fields between the end of the semi-sphere and the center, non-negligible.
Thanks once again.TESL@ said:The regular Faraday cage is used but I don't know about the last device, I just made it up.