Electrostatics and Coulombines: Diagram Included.

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SUMMARY

The discussion centers on calculating the charge of two small spheres, each with a mass of 0.1g, suspended and repelling each other due to equal charges. The spheres are 24cm apart, and using Coulomb's law, the charge is determined to be approximately 6.86 x 10^-8 coulombs. The participants clarify the application of forces in the context of electrostatics, emphasizing that the force exerted by one sphere on the other is equal in magnitude but opposite in direction, in accordance with Newton's third law.

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  • Understanding of Coulomb's Law and electrostatic forces
  • Basic knowledge of Newton's laws of motion
  • Ability to convert units (grams to kilograms, Newtons, etc.)
  • Familiarity with basic trigonometry for force diagrams
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  • Learn about the principles of forces in equilibrium and their graphical representation
  • Explore unit conversion techniques relevant to physics problems
  • Investigate online resources for practice problems in electrostatics
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Homework Statement


2 small spheres each having a mass of 0.1g are suspended from the same point on silk threads 20cm long. When given equal charges, they repel, resting 24cm apart. Calculate charge of each.


Homework Equations


F(w)=mg(a)
F=kQ(1)Q(2)/d^2
k=8.987x10^9 N*m^2 / c^2

The Attempt at a Solution


I converted grams to kilograms.. 1 x 10^-4 kg
kilograms to Newtons/weight..9.8*10^-4N

blah blah..
F=kQ(1)Q(2)/d^2
(7.35*10^-4N)(.24^2)(8.987*10^9 N*m^2/c^2)=Q^2
Q=6.86*10^-8C

http://i80.photobucket.com/albums/j199/pugfug90/physucks.gif
Here's some work and a diagram. I am 99% sure that the answer is 6.9*10^-8 coulombs. However! I don't understand.. If I used trig to find half of the total force (in the triangle diagram).. why do I use the full distance?
 
Last edited by a moderator:
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If I understand what you're asking: You aren't finding just half the force. Coulomb's law obeys Newton's third law, so the force exerted on Q1 by Q2 has to have the same magnitude as the force of Q2 on Q1, it is just in the opposite direction.
 
AHHHHHHH

But mah physical teacher drew this line between both balls (for notes) and labeled it force.. Hage, that kind of makes sense. Thanks for help. So force isn't really "half", therefore just because I'm using "half force" doesn't mean I use half distance..?

Anyone want to do the problem, starting with..

"2 small spheres each having a mass of 0.1g are suspended from the same point on silk threads 20cm long. When given equal charges, they repel, resting 24cm apart. Calculate charge of each."

Also, any online links with similar problems?
----
coulaw.gif

http://i80.photobucket.com/albums/j199/pugfug90/physicismean.gif
Because of that image, and a nice guy that kind of explained it.. I made this graphic and I hope it shows that I understand:) What do you guys think of it?
 
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Hey hey can anyone confirm my work of art?
 
heyheyheyheyhey
 

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