# Electrostatics - Magnitude and direction of electric force

## Homework Statement

What are the magnitude and direction of the electric force on the +2.0x10^-6 charge shown in the diagram (included in the attachment)?

F = kq1q2/r^2

## The Attempt at a Solution

I used the Ep = kq1q2/r^2 equation and plugged in the numbers but didn't get any of the provided answers and I was just wondering what I was doing wrong?

What I did was:
F= kq1q2/r^2
F= (9.00x10^9)l(-6.0x10^-6)(-7.0x10^-6)l/(4.0)^2 [note: l l here means absolute value]
F= 0.23625

the answer I got was that, but it matches up with none of the provided answers?

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What I did was:
F= kq1q2/r^2
F= (9.00x10^9)l(-6.0x10^-6)(-7.0x10^-6)l/(4.0)^2 [note: l l here means absolute value]
F= 0.23625 Not sure what you did here, since you were asked to find the force on the +2.0x10^-6 charge (the middle charge).

What force does the left charge exert on the middle charge?
What force does the right charge exert on the middle charge?

What's the net force on the middle charge?