Electrostatics - Magnitude and direction of electric force

  • #1

Homework Statement


What are the magnitude and direction of the electric force on the +2.0x10^-6 charge shown in the diagram (included in the attachment)?


Homework Equations


F = kq1q2/r^2


The Attempt at a Solution


I used the Ep = kq1q2/r^2 equation and plugged in the numbers but didn't get any of the provided answers and I was just wondering what I was doing wrong?

What I did was:
F= kq1q2/r^2
F= (9.00x10^9)l(-6.0x10^-6)(-7.0x10^-6)l/(4.0)^2 [note: l l here means absolute value]
F= 0.23625

the answer I got was that, but it matches up with none of the provided answers?
 

Attachments

Last edited:

Answers and Replies

  • #2
Doc Al
Mentor
44,990
1,263


What I did was:
F= kq1q2/r^2
F= (9.00x10^9)l(-6.0x10^-6)(-7.0x10^-6)l/(4.0)^2 [note: l l here means absolute value]
F= 0.23625
:confused: Not sure what you did here, since you were asked to find the force on the +2.0x10^-6 charge (the middle charge).

What force does the left charge exert on the middle charge?
What force does the right charge exert on the middle charge?

What's the net force on the middle charge?
 

Related Threads on Electrostatics - Magnitude and direction of electric force

Replies
4
Views
4K
Replies
3
Views
12K
Replies
2
Views
1K
Replies
4
Views
644
Replies
1
Views
2K
  • Last Post
Replies
3
Views
3K
Replies
2
Views
1K
Replies
3
Views
1K
Replies
2
Views
13K
Replies
6
Views
4K
Top