Elevator Problem: Max Mass Calculation (10kN, 2m/s2)

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To determine the maximum mass of the elevator and its occupants, apply Newton's second law, F = ma, using the maximum force of 10kN and the given acceleration of 2m/s². The net force acting on the elevator must account for both the gravitational force and the tension in the cable. By rearranging the formula to solve for mass, m = F/a, the calculation leads to a maximum mass of 5000 kg. The discussion emphasizes identifying the forces acting on the elevator and calculating the net force to arrive at the correct answer. Understanding these principles is crucial for solving the problem accurately.
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Homework Statement



An elevator cable can hold a maximum of 10kN and has a maximum accelleration of 2m/s2. Determine the maximum mass of the elevator and participants.


i need some help, can't figure this out at all. thanks in advance
 
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The obvious thing here is to use F = ma
You know F and you know a... find m.
If you get stuck get back to me
 
I tryed putting them just straight in but that does not work.

I forgot to put the multiple choice, it might help

A. 1050kg
B. 1280kg
C. 0.8466kg
D. 1.28kg
E. 890kg
F. 10009.81kg
G. 846.74kg
H. 9.901kg
I. 650kg
 
Identify the magnitude and direction of the forces acting on the elevator, both known and unknown. There are 2 forces acting in the vertical direction. Find the net force, and use Newton's 2nd law, F_net = ma.
 

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Thread 'A cylinder connected to a hanging mass'

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