Solving for I2 in a Circuit: What Am I Doing Wrong?

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SUMMARY

The discussion focuses on solving for the current I2 in a circuit involving three currents (I1, I2, I3) using Kirchhoff's laws. The user initially set up their equations incorrectly by including an unnecessary junction at point A and misidentifying the loops. After correcting the node definitions and realizing that only two loops and one junction at B are needed, the user successfully solved for the unknown currents. The key equations referenced include ΣIin=ΣIout and ∫dv=0.

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Homework Statement


I am attempting to solve the circuit for three currents (I1, I2, I3). I am starting with I1 in terms of I2, then using a third equation to solve for I2 in terms of E and R. I wrote my loops at the bottom of the page. I am using Loop 1 @ B, Loop 2 @ B, and Junction at B to solve for I2.
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Homework Equations


ΣIin=ΣIout
∫dv=0

The Attempt at a Solution


Page 2 has all my algebra to solve for I2 first. I reversed the sign of Loop 3 at B, but I don't think that is what is throwing off my answer. I have a measured I2 value to compare against and my answer is nowhere near it. Not sure what I am doing wrong.
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The first issue is that A is not a junction. Also the system looks over determined. There are only two loops so you only need two currents.
 
Thank you for your reply. This is a lab experiment so I have to follow (i.e. use) the circuit diagram I am given. You are absolutely right, I need only the two loops and one junction at B to solve for the 3 currents. I am more looking to see if my loop equations are setup correctly. Then I can move on to what I did wrong in my calculations.
 
Okay, in that case the nodes A and C are incorrect.
 
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Thank you for your observation. I was able to correct the nodes and solve for each unknown current. Even found out how to solve using only one node!
 

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