EML3005 Mechanical Design Project Shaft Analysis

Click For Summary
SUMMARY

The forum discussion centers on the EML3005 Mechanical Design Project, specifically focusing on shaft analysis involving a V-belt pulley and gear system. The project requires the creation of shear and moment diagrams, torque diagrams, and a conceptual design of the shaft. Key parameters include a shaft transmitting 10 kW at 1200 rpm, a pitch diameter of the pulley at 250 mm, and an involute gear with a pitch diameter of 6 inches. The user seeks guidance on how to relate theoretical formulas to practical applications in their project.

PREREQUISITES
  • Understanding of Free Body Diagrams (FBD)
  • Knowledge of shear and moment diagrams in mechanical design
  • Familiarity with torque calculations and gear mechanics
  • Basic principles of mechanical design and shaft configurations
NEXT STEPS
  • Research the creation of shear and moment diagrams for shafts
  • Learn about torque transmission in mechanical systems
  • Study the design principles for keyways and axial holding methods in shafts
  • Explore the application of involute gear design and its calculations
USEFUL FOR

Mechanical engineering students, design engineers, and anyone involved in mechanical design projects requiring shaft analysis and torque transmission understanding.

stefan1988
Messages
8
Reaction score
0
I need some help Desperately for this class.

this project is 10% of my grade and I'm doing really bad in this class >_<.
I have read the book but is all talking about is bunch of formulas that i have no idea how to relate them to this.
I uploaded the diagram as well that was part of the Project information


i don't want the answers necessarily but point me in the right direction
X value=5
Y value =8

I uploaded the diagram explaining it a little bit more
at the moment I am confused as hell as to do what to do or where to even start from
Code:
Assume that x is the second number in your UFID and that y is the fourth number.  
(For example, if your UFID is 8765-4321, then x=7 and y=5.)

See the sketches below.
You have a shaft that is loaded by an overhanging V-belt pulley and a gear between the bearings.   The center of the pulley is  1x0 mm  from the center of the bearing.
The belt tensions on the pulley are  y0o  above the opposite horizontal direction of the transmitted force (Wt) applied to the gear.
The shaft transmits 10 kW at 1200 rpm.
The pitch diameter of the pulley is 250 mm.  TB = 5TA.
The involute gear is 20o, P=6, and has a pitch diameter of 6 inches.
Assume the forces are in the centers of the gear, pulley, and bearings.

Please create a report which includes the following:

a.  a printed cover sheet with your name on it

b.  shear and moment diagram for the shaft for the horizontal direction

c.  shear and moment diagram for the shaft for the vertical direction

d.  a diagram of the maximum bending moment at each point in the shaft

e.  a diagram of the torque at each point in the shaft

f.  (Doing no calculations at this time and assuming your design concepts may change after you do detailed design in Part B) sketch a conceptual design of the shaft.  The shaft sketch should show provisions for transmitting torque to the gear and pulley (keyways? holes? etc.) and methods for holding the components axially (shoulders? holes? snap ring grooves? etc.).  Assume (for now) that the pulley and gear have about 30 mm wide hubs and that the bearings are about 15 mm wide.  Put no dimensions on the shaft at this time, but the design should be reasonable.



so far all i can think of is do FBD Diagram
1st question would be what is the horizontal direction? is it the way is already drawn in the diagram or is that vertical direction?

2nd question would be
if i do a FBD the way is show there
the reactions for Bearing,Gear,V pulley?

By RA i mean Reaction at A for first bearing
for Bearing is it only RAY i should take into account? or do i take into account RAZ?
for the Gear is it only Torsion? that i take into account or does it have RAY and RAZ


Any help would be Extremely appreciated
 

Attachments

  • Diagram.png
    Diagram.png
    7.7 KB · Views: 1,055
Physics news on Phys.org
I did some more work on it maybe somebody can help double check if I am doing this calculations right

WT=(60,000*H)/(π*D*N) H=power,KW D=gear diameter,mm N=speed rev/min
information given shaft transmits 10KW at 1,200 rpm
pitch diameter of gear 6inches since D has to be in mm i do conversion of
6in*(25.4mm/1 in)=152.4 so D=152.4mm

WT=1.04432KN
to find the normal force pushing on gear
WR=1.04432KN*Tan(20°)=.380101KN

now I am trying to solve for the pulley
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
13
Views
7K
Replies
5
Views
4K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K