Energy density of an electromagnetic field

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Discussion Overview

The discussion revolves around the energy density of an electromagnetic field in the context of linear dielectrics. Participants explore the relationship between macroscopic and microscopic electrodynamics, and the implications of integrating over free versus bound charges.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether the first result for energy density neglects the energy from bound charge and seeks clarification on why certain formulae break down in the presence of dielectrics.
  • Another participant asserts that the energy density expression for macroscopic electrodynamics is correct and references Markovian linear-response theory to explain the relationship between the electric displacement field and the electric field.
  • A third participant suggests consulting Griffith's Electrodynamics for further discussion on energy in dielectric systems, pointing to specific sections for reference.
  • A later reply indicates that the previous explanations have clarified the initial confusion regarding the topic.

Areas of Agreement / Disagreement

Participants do not reach a consensus, as there are differing views on the treatment of bound charges and the applicability of certain equations in the context of dielectrics.

Contextual Notes

There are limitations regarding the integration of free and bound charges, as well as the assumptions made in transitioning between macroscopic and microscopic frameworks, which remain unresolved.

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The energy density of an electromagnetic field with a linear dielectric is often expressed as
1994848e8909b58aaa7dfa748264681c15b04cdb.png
. It is also known that energy can be found by
90ce12f273329132bc0a22e77cabd6fadd9317ec.png
. Using the latter, the energy density is found to be
2b95635ceca0346d915aadc5ef5f3f8047d12dd6.png
, as is well known. If you integrate the latter only over free charge and ignore bound charge, you write
a3e754ebda6b4b4d609f6ac85bb3d8b3f6fa3516.png
, use integration by parts, and obtain the first result. Does the first result neglect the energy from bound charge? If not, why does
2b95635ceca0346d915aadc5ef5f3f8047d12dd6.png
break down (I.e. why can’t one find the energy with a dielectric by treating the bound charge as its own independent charge arrangement and using formulae for a vacuum?)
 

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You are mixing macroscopic with microscopic electrodynamics. For macroscopic electrodynamics ##u=\vec{E} \cdot \vec{D}/2## is correct. Within Markovian linear-response theory ##\vec{D}=\epsilon \vec{E}=\epsilon_0 \epsilon_r \vec{E}##.
 
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I see. Makes perfect sense now. Thanks!
 

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