Energy in a long inextensible string

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The discussion focuses on calculating the maximum kinetic energy and total energy of a string oscillating as a standing wave with fixed ends. The solution involves treating the string as a series of harmonic oscillators, deriving the maximum kinetic energy from the wave equation, and integrating to find the total energy. The integration confirms that the maximum kinetic energy equals the total energy of the system, expressed as M(wA)^2. A suggestion is made to ensure the frequency is correctly represented in terms of angular frequency before finalizing the answer. The approach taken is validated as correct.
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Homework Statement


Find the maximum kinetic energy and total energy of the system if a string(with uniform linear density) of length L and mass M is oscillating as a standing wave with two fixed ends in its fundamental frequency f with amplitude 2A

Homework Equations


let x=0 and x=L be the coordinates of each end .
Assuming the solution to the wave equation is A(cos(kx-wt)-cos(kx+wt))
=2Asin(kx)sin(wt)
Thus the amplitude as a function of x is 2Asin(kx)
and kL=pi

w=2*pi*f

The Attempt at a Solution



Treating the string as a series of harmonic oscillator ,
the max.KE of each oscillator is then (1/2)[(w*2Asin(kx))^2](M/L)(dx) <--basically just half mv^2

then , integrating the expression w.r.t. x from x=0 to x=L gives

(M/L)(wA)^2* the integral of 2(sin(kx))^2

=(M/L)(wA)^2* the integral of 1-cos(2kx)
=(M/L)(wA)^2*L
=M(wA)^2

and by conservation of energy , max kinetic energy=the total energy of the system

I'm not really sure if it's a correct approach
 
Last edited:
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throneoo said:
View attachment 74863

Homework Statement


Find the maximum kinetic energy and total energy of the system if a string(with uniform linear density) of length L and mass M is oscillating as a standing wave with two fixed ends in its fundamental frequency f with amplitude 2A

Homework Equations


let x=0 and x=L be the coordinates of each end .
Assuming the solution to the wave equation is A(cos(kx-wt)-cos(kx+wt))
=2Asin(kx)sin(wt)
Thus the amplitude as a function of x is 2Asin(kx)
and kL=pi

w=2*pi*f

The Attempt at a Solution



Treating the string as a series of harmonic oscillator ,
the max.KE of each oscillator is then (1/2)[(w*2Asin(kx))^2](M/L)(dx) <--basically just half mv^2

then , integrating the expression w.r.t. x from x=0 to x=L gives

(M/L)(wA)^2* the integral of 2(sin(kx))^2

=(M/L)(wA)^2* the integral of 1-cos(2kx)
=(M/L)(wA)^2*L
=M(wA)^2

and by conservation of energy , max kinetic energy=the total energy of the system

I'm not really sure if it's a correct approach
Yes, that looks correct to me. :)

One thing though, the problem statement stated the frequency in terms of simple frequency, f. You should make the appropriate substitution your representation with ω = 2πf before submitting your final answer.

But yeah, that looks to be a valid approach.
 
alright. thank you very much
 
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