Energy of the Simple Harmonic Oscillator

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SUMMARY

The discussion focuses on calculating the speed of a 50.0-g mass attached to a spring with a force constant of 35.0 N/m when the displacement is 1.00 cm. The total mechanical energy of the system is established as E = 0.5kA², where A is the amplitude of 4.00 cm, resulting in a total energy of 0.0004 J. The kinetic energy (KE) and potential energy (PE) relationship is emphasized, leading to the equation mv²/2 = E - kx²/2, which allows for the determination of speed at various displacements.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with kinetic and potential energy equations
  • Knowledge of conservation of energy in mechanical systems
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of energy equations in simple harmonic motion
  • Learn about the relationship between amplitude, frequency, and energy in oscillatory systems
  • Explore the effects of mass and spring constant on oscillation speed
  • Investigate real-world applications of simple harmonic oscillators in engineering
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Students in physics, educators teaching mechanics, and engineers working with oscillatory systems will benefit from this discussion.

adashiu
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A 50.0-g mass connected to a spring with a force constant
of 35.0 N/m oscillates on a horizontal, frictionless
surface with an amplitude of 4.00 cm. Find the speed of the mass
when the displacement is 1.00 cm.

Can I use here something like :

\frac{mv2}{2}=0,5kx2?
 
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Use conservation of energy. What's the total energy at any point in the motion?
 
The total energy is 0,5kA2=0,028

But how to express an energy at displacement 1cm? :blushing:
 
Hint: Total mechanical energy is the sum of kinetic and potential energy.
 
Yes i know that but there is no formula with velocity...

I've got to use mv2/2??
 
adashiu said:
Yes i know that but there is no formula with velocity...

I've got to use mv2/2??
Yes, that's the kinetic energy. What's the potential energy at any point?
 
Potential energy is 0?
 
adashiu said:
Potential energy is 0?

Total energy is : 0,5kA2=4*10-5

mv22/2=4*10-5

v=0.04, of course it seems not to be correct :(
No. Hint: Potential energy is zero when x = 0 and maximum at x = A. What's the PE at an arbitrary position?
 
adashiu said:
\frac{mv2}{2}=0,5kx2


?
Your equation defines a condition when a half of the energy is in speed and another half in the displacement.
Ek + Ep = E
E = kA2/2
mv2/2 = E - kx2/2
 

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