Energy required per day for survival by an individual

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SUMMARY

The average energy requirement for an individual performing normal activities is approximately 2,000 kilocalories per day, which translates to about 8.4 megajoules or 2.3 kilowatt-hours (kWh). A typical human burns energy at a rate of approximately 100 watts, leading to a total daily energy consumption of around 2.4 kWh. This discussion clarifies the conversion between food calories and electrical energy, emphasizing that a food calorie is equivalent to a kilocalorie.

PREREQUISITES
  • Understanding of energy units: kilocalories, kilojoules, and kilowatt-hours
  • Basic knowledge of human metabolism and energy expenditure
  • Familiarity with energy conversion calculations
  • Awareness of average human energy consumption rates
NEXT STEPS
  • Research the relationship between kilocalories and kilojoules for various foods
  • Explore human energy expenditure during different physical activities
  • Learn about the efficiency of converting food energy to electrical energy
  • Investigate the implications of energy consumption on health and lifestyle
USEFUL FOR

Health professionals, nutritionists, fitness enthusiasts, and anyone interested in understanding human energy requirements and their conversion to electrical energy.

n.karthick
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I want to know how much energy is required by an average individual per day for his survival, assuming he is doing normal work. is there any rough estimate? (say some thousands of joules !). I like to know this rough value and I want to convert this is to electrical equivalent (i.e, in kWhr). In brief, assuming that a human can live by consuming only electricity, how much units (kWhr) is required for him every day?
 
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Two thousand calories per day for an average person so: 2 kcal = 8.3736 kilojoules = 0.002326 kwhr

iron_john
 
This is wrong. A food calorie is actually a kilocalorie. So it is actually 8.4 MJoules, or 2.3 kWh. You burn energy at about 100W - 100W * 24 Hr = 2.4 kWh.
 

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