Energy Sharing in Elastic Collisions

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In an elastic collision involving a stationary object with mass mb and a moving object with mass ma, both kinetic energy and momentum are conserved. To find the percentage of energy each object retains post-collision, one must apply the conservation equations for kinetic energy and momentum. The moving mass can be denoted as m with an initial velocity u, while the stationary mass can be denoted as M. After establishing the final velocities v for m and w for M, the equations can be set up to solve for the retained energy percentages. The discussion emphasizes the need to simplify notation for clarity in calculations.
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A stationary object with mass mb is struck head-on by an object with mass ma that is moving initially at speed v0.
If the collision is elastic, what percentage of the original energy does each object have after the collision?

I don't know how to find percentage.
 
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Is the collision assumed to be perfectly elastic? i.e. is the total kinetic energy assumed to be conserved?
 
kinetic energy conserved
 
There are two principles you can use. Do you know which principles?
 
kinetic energy & momentum
but how to calculate
 
Correct.
First I would simplify the notation.
Why not call the stationary mass M and the other mass m.
Let m have intial velocity u and let final velocities of m be v and that of M be w.
Now apply those two principles.
 
conservation of KE: (1/2)mu^{2} = ...
conservation of linear momentum: mu =...
 
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