Energy stored in a single capacitor

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The discussion revolves around calculating the energy stored in a capacitor network with a potential difference of 12.0V. The total energy stored in the network has been determined to be 158 μJ. To find the energy stored in the 4.80 μF capacitor, the relationship between charges in a series capacitor circuit is emphasized, noting that the charge is the same across all capacitors in series. The equivalent capacitance of the circuit is calculated to be 2.18 μF, and the relationship between individual charges and the total charge is explored. Understanding these relationships is crucial for solving the problem correctly.
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Homework Statement


For the capacitor network shown in the Figure (Figure 1) , the potential difference across is 12.0 . (Figure is attached by the way)
A)Find the total energy stored in this network. (I already found this to be 158 μJ)
B)Find the energy stored in the 4.80- capacitor.


Homework Equations


U=1/2 CV^2


The Attempt at a Solution


I would imagine that you need to subtract the amount of energy in the parallel branches from the total amount of energy of the system, but I don't know how to do this without knowing the charge.
 

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Another equation that I would add to your list is Q = CV (Charge = Capacitance x voltage).

I will give you a hint in the form of two questions:
1) How are the charges in a series capacitor circuit related?
2) How does the charge on one of the capacitors in a series capacitor circuit related to the total charge in the circuit?
 
misterc said:
Another equation that I would add to your list is Q = CV (Charge = Capacitance x voltage).

I will give you a hint in the form of two questions:
1) How are the charges in a series capacitor circuit related?
2) How does the charge on one of the capacitors in a series capacitor circuit related to the total charge in the circuit?

1) Q=CV as your equation said.
2) (Qtotal/#of capacitors)=Charge per capacitor?
 
Since you got part a), I'll assume you can convert between series, parallel and total capacitance.

So, in your problem, we can model the circuit as three capacitors in series. Correct?

Let's call the three capacitors C1, C2, C3 where C1 = 8.6 uF, C2 = 4.8 uF, and C3 = 7.5 uF. Correct?

Let's call Ceq the total equivalent capacitance = 2.18 uF. Correct?

My questions then are:
How are Q1, Q2, and Q3 related?
How does Q2 (since that's the capacitor in question), relate to Qeq?
 
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