(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The rocket sled starts from rest and accelerates at a = 30 + 2t until its velocity is 400m/s. It then hits a water brake and its acceleration is a = -0.003v^2 m/s^2 until its velocity decreases to 100 m/s. What total distance does it travel?

2. Relevant equations

v = u + at

s = ut + at^2/2

v^2 = u^2 + 2as

3. The attempt at a solution

I'm pretty sure my first part is correct but here it is anyway:

v = u + at

v = u + (30 + 2t)t

*Sub in values and i get t = 8.508s, then i get s = 1701.652m from the other equation

For the next part ive done this:

a = -0.003v^2

v dv/dx = -0.003v^2

dv/v = -0.003dx *integrate both sides

ln(v) = -0.003x + C

when v = 400, x = 0, C = ln(400)

ln(v) = -0.003x + ln(400)

so when v = 100, i get x = 462.098m

So the total distance i get is 2163.750m but the answer says 2300m....

Where did i go wrong or is the answer given incorrect? :S

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# Homework Help: Engineering Dynamics (Motion related)

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