# Entanglement and Poker

Let me see if I understand this correctly, please critique. Say, 6 players are playing a game of hold em. This means that in a randomly shuffled deck, two cards will be dealt to each player totaling twelve cards. Say no player has observed their cards. At this point the cards are in superposition. Players then observe their cards and instantaneously certain wave functions collapse. Say I have a 2, J. And the flop is 9, K, 2. There still exists a possibility of getting a straight 9-K if a Q and a 10 come up on the turn and the river. The dealer turns the next card and it is a 4. Instantly the wave function of the straight collapse to 0. Now there is a 0% chance of getting a straight. If there are 9 quantum states of poker (high card, pair, 2 pair, three of a kind, straight, flush, boat, four of a kind, straight flush), then wouldnt a player just have to collapse as many possible quantum states to suggest the best decision to make? Whether to fold, call, or raise that is. Thoughts please.

## Answers and Replies

DevilsAvocado
Gold Member
I have never heard of a deck of cards in a superposition or entanglement... it might work in Vegas, but the chances to shield the cards against environmentally induced quantum decoherence are not overwhelming...

If you want to understand the basics in EPR-Bell and entanglement, I recommend reading A Simple Proof of Bell's Theorem.