Entropy/ 2nd law of thermodynamics

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Homework Help Overview

The discussion revolves around the entropy change associated with mixing two equal masses of water at different temperatures, T1 and T2, under isobaric and adiabatic conditions. Participants are tasked with deriving an expression for the total entropy change in the universe during this process.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between heat transfer and entropy change, questioning the validity of using reversible processes to calculate total entropy. There is an attempt to find the equilibrium temperature by setting heat exchanges to zero, but uncertainty remains about the correctness of this approach. Some participants express confusion about how to account for the isobaric mixing condition and the implications of vapor pressure.

Discussion Status

The discussion is ongoing, with participants sharing their attempts to understand the problem and questioning the assumptions involved. There is no clear consensus yet, but multiple interpretations and approaches are being explored, indicating a productive exchange of ideas.

Contextual Notes

Participants note the complexity of the problem, particularly regarding the assumptions of saturation and the nature of the mixing process. There is a recognition that the process may not be straightforward due to the irreversible nature of the mixing and the need to consider vapor pressure.

BingoMan
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Homework Statement


A mass of water at T1 is isobarically and adiabatically mixed with an equal mass of water at T2. Show that the entropy change in the universe is 2*m*Cp*ln[(T1 + T2)/(2*SQRT(T1*T2))]

Homework Equations


I'm assuming
dS = dq/T
q = m Cp dT

The Attempt at a Solution


At the very beginning I was just using q = cpdT and getting total entropy = to m Cp ln(T2/T1) but that might be because that takes the process as reversible and this is an irreversible function

Next, I tried to find the equilibrium temperature by setting q1(using T1 and Tf) and q2 (using T2 and Tf) = 0 but I don't believe that is true and I couldn't figure out a way to get the equation given in the question.

It seems like it would be simple but I must be missing something.

Please help
 
Last edited:
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Is this answer as simple as finding the equilibrium temperature then using that to find the entropy change in both masses and subtracting those?? If that's the case, then how does one figure out the equilibrium temp because I tried that to no avail.
 
BingoMan said:

Homework Statement


A mass of water at T1 is isobarically and adiabatically mixed with an equal mass of water at T2. Show that the entropy change in the universe is 2*m*Cp*ln[(T1 + T2)/(2*SQRT(T1*T2))]


Homework Equations


I'm assuming
dS = dq/T
q = m Cp dT

The Attempt at a Solution


At the very beginning I was just using q = cpdT and getting total entropy = to m Cp ln(T2/T1) but that might be because that takes the process as reversible and this is an irreversible function

Next, I tried to find the equilibrium temperature by setting q1(using T1 and Tf) and q2 (using T2 and Tf) = 0 but I don't believe that is true and I couldn't figure out a way to get the equation given in the question.

It seems like it would be simple but I must be missing something.

BingoMan said:
Is this answer as simple as finding the equilibrium temperature then using that to find the entropy change in both masses and subtracting those?? If that's the case, then how does one figure out the equilibrium temp because I tried that to no avail.
It is not a simple question.

I think you are expected to take into account the vapour pressure of the water and assume that it is saturated at all times.

AM
 
I thought I might have to do that but it is isobarically mixed so I do not know how to deal with that
 

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