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Equation a plane through 3 points.

  1. Oct 7, 2008 #1
    1. The problem statement, all variables and given/known data
    Find an equation of the plane through the points: A=(1,2,3), B=(0,1,3) and C=(2,14)

    2. Relevant equations
    r= r[0]+tv
    vector equation of a plane: a(x-x[/0)+ b(y-y[/0]) + c(z-z[/0])=0

    3. The attempt at a solution
    Since I am given three points and no vector, I am a bit confused on what to do. I tried to compute the normal vector, and got:

    Any corrections/suggestions on what to do next?
  2. jcsd
  3. Oct 7, 2008 #2


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    Science Advisor
    Homework Helper

    (1,2,3)-(0,1,3) is (1,1,0) not (1,1,3). And that's a tangent vector, not a normal vector. Hint: you can find a normal vector if you can find two different tangent vectors and take the cross product.
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