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## Homework Statement

Find an equation for the plane containing the lines:

x-3= 4t , y-4 = t, z-1 = 0

x+1 = 12t, y-7 = 6t, z-5 = 3t

## The Attempt at a Solution

I found the equations of both lines.

First line:

(3, 4, 1) + t(4, 1, 0)

(-1, 7, 5) + t(12, 6, 3)

Now I take the cross product of (4, 1, 0) and (12, 6, 3) to get (3, -12, 12)

I found two answers from reviewing this question and I'm confusing myself, so I was wondering which answer is right. (If any)

3x - 12y + 12z = 27

or

3x - 12y + 12z = 0

Thanks in advance.