Equation of continuity - what if more openings are added?

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SUMMARY

The equation of continuity, expressed as A1V1 = A2V2, applies regardless of the number of openings in a system. In the case of a showerhead with 20 holes, A2 represents the total cross-sectional area of all openings combined, calculated as A2 = 20*(10^-3 m)^2. The velocity of the fluid exiting each hole, denoted as V2, remains uniform across all openings due to equal area distribution. Therefore, the equation does not require division by the number of holes.

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RUphysics3
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The equation states that A1V1=A2V2. What about in a situation like a showerhead, where it's one long pipe/tube, then opens up to say, 20 holes. Is it now A1V1=A2V2/20 ? why/why not?
 
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A2 is the total area, regardless of how many holes it is divided up into. That is because over any length of time, the total flow in equals the total flow out. So don't divide by 20.
 
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There are 20 holes, each with an area of (10-3m)2, so the total area of all 20 of them is A2 = 20*(10-3m)2. So the equation (shown on the first line of the answer) is still A1V1 = A2V2.
 
okay, so A2 , if there are 20 openings, is the area of ALL 20 openings, while v2 is the speed of the liquid out of one of the openings, which is uniform through all twenty of them as they are equal areas?
 
RUphysics3 said:
okay, so A2 , if there are 20 openings, is the area of ALL 20 openings, while v2 is the speed of the liquid out of one of the openings, which is uniform through all twenty of them as they are equal areas?
That sounds right to me.
 

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