1. The question was find the area between the curves using DOUBLE Integrals Area between: r = sin theta r = cos theta well to draw them i made them into cartesian form by r^2 = rsin theta r^2 = rcos theta so x^2 + y^2 = y x^2 + y^2 = x completing square 1) x^2 + (y - 1/2)^2 = 1/4 2) (x - 1/2)^2 + y^2 = 1/4 these are two circles their intersection or bounded region that we need to find the area is like a disc... I know if i use the double integral Integral of (Integral of 1) dA OVER D where D is the intersection bounded area i get the area i need.... but I dont know how to define that region if someone can help me define the region it will be helpful I know THETA will change from 0 to pi/2 but R will change from 0 to some equation of that area but i dont know how to find that equation!! HELP!!