Equation of Motion of a System of Springs (System Dynamics)

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SUMMARY

The discussion focuses on the equation of motion for a system of springs, specifically addressing two methods of deriving the equation. The first method combines the spring constants using the formula Keq = K1⋅K2/(K1+K2), leading to the equation M×x" + (α(K1)/(1+α)) × (x + δst) = mg, which simplifies to M×x" + (x) × (α(K1)/(1+α)) = 0. The second method, which was initially questioned, is confirmed incorrect; the correct relationship is K2(x-y) = K1x, aligning it with the first solution's results.

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  • Understanding of spring constants and series combinations
  • Familiarity with Newton's second law of motion
  • Knowledge of free body diagrams in mechanics
  • Basic principles of system dynamics
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Mechanical engineers, physics students, and anyone involved in analyzing dynamic systems with springs will benefit from this discussion.

LostMechE901
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Moved from a technical forum, so homework template missing
I'm having trouble understanding the forces involved when defining the equation of motion for this particular problem.
Question 4.JPG


So... I've seen the answer for the eq. of motion worked two different ways. The first way involves combining the spring series into Keq = K1⋅K2/(K1+K2). The answer, plugging in α(K1) for K2, comes out to be M×x" + α(K1)/(1+α) × (x + δst) = mg. The weight and static deflection cancel out, rendering the final answer M×x" + (x) × (α(K1)/(1+α)) = 0.

The 2nd way I've seen this problem worked is as follows:
Capture.JPG


In the 2nd solution, I don't understand how he figured the proportion K1⋅x = K2⋅y. When drawing my free body diagrams of the springs enacting forces upon each other, the only equations I can devise are K2(y-x) ∧ and K1⋅y ∧.

Is the 2nd solution incorrect? If it can be worked that way, how do you figure that relationship?

*Edit* I Just realized there is a specific engineering problem help section for threads like this. I apologize for misplacement in advance. :oops:
 

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The 2nd solution is incorrect. The equation should read: $$K_2(x-y)=K_1x$$ This leads to the same result as in the first solution.
 

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