MHB Equation of Plane Through Origin & Perpendicular to Vector (1,-2,5)

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The equation of a plane through the origin and perpendicular to the vector (1,-2,5) can be derived using the formula a(x-x0) + b(y-y0) + c(z-z0) = 0. In this case, since the plane passes through the origin, the equation simplifies to 1(x-0) - 2(y-0) + 5(z-0) = 0. This results in the equation x - 2y + 5z = 0. The discussion highlights the process of finding the equation and confirms the solution. The final equation represents the desired plane in three-dimensional space.
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find the equation of the plane through the origin and perpendicular to the vector (1,-2,5). this is the only relevant equation i have found $a(x-x_0)+b(y-y_0)+c(x-x_0)=0$
 
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nevermind. i got it.
 

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