- #1

- 123

- 0

400sinA + 500cosA = 600

Just doin some statics problems and for one of 'em I needed to find A. Can anyone tell me how its done.

Thanks

- Thread starter strokebow
- Start date

- #1

- 123

- 0

400sinA + 500cosA = 600

Just doin some statics problems and for one of 'em I needed to find A. Can anyone tell me how its done.

Thanks

- #2

- 53

- 0

See this recent thread: https://www.physicsforums.com/showthread.php?t=164679

- #3

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 956

[tex]100\sqrt{41} sin(A+ arccos(4/\sqrt{41})= 600[/tex]

[tex]sin(A+ arccos(4/\sqt{41})= 6/\sqrt{41}[/tex]

so [itex]A+ arccos(4/\sqrt{41})= arcsin(6/\sqrt{41})[/itex] and, finally,

[tex]A= arcsin(6/\sqrt{41})- arccos(4/\sqrt{41})[/tex]

According to my calculator, that is about 0.318.

- #4

- 1,056

- 0

Using [tex]sin(x)=\sqrt{1-cox^2(x)}[/tex] I arrived also at a second answer, x=1.0315.

- #5

- 1,482

- 3

- #6

- 1,425

- 1

Huh, I think he is adding moments of forces.

- Last Post

- Replies
- 6

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 5

- Views
- 714

- Last Post

- Replies
- 8

- Views
- 3K

- Last Post

- Replies
- 5

- Views
- 2K

- Last Post

- Replies
- 3

- Views
- 1K

- Last Post

- Replies
- 2

- Views
- 1K

- Last Post

- Replies
- 4

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 676

- Last Post

- Replies
- 2

- Views
- 3K