Equations of motion for Lagrangian of scalar QED

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The discussion focuses on deriving the equations of motion for the Lagrangian of scalar quantum electrodynamics (QED). The initial equation of motion for the scalar field is presented, but the author expresses uncertainty about its correctness. A correction is suggested regarding a term in the first equation, indicating it should involve A^2*phi instead of A*phi. Additionally, it is noted that the term related to the 4-divergence of the vector potential can be simplified by choosing a specific gauge. Overall, the conversation revolves around ensuring the accuracy of the equations of motion in scalar QED.
BobaJ
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Homework Statement
I have the Lagrangian for scalar electrodynamics given by:
$$\mathcal{L}=-\frac{1}{4}F_{\mu\nu}(x)F^{\mu\nu}(x)+(D_\mu\varphi(x))^*(D^\mu\varphi(x))-V(\varphi^*(x)\varphi(x)) $$
where ##F_{\mu\nu}(x)=\partial_\mu A_\nu(x)-\partial_\nu A_\mu(x)## is the electromagnetic field strength tensor, ##D_\mu=\partial_\mu+ieA_\mu## ist the covariant derivative, e is the electric charge and ##V(\varphi^*\varphi)=m^2\varphi^*\varphi+\lambda(\varphi^*\varphi)^2## is the potential of the scalar field.

I have to determine the equations of motion for both the complex scalar field ##\varphi## and the electromagnetic field ##A_\mu## by using the Euler-Lagrange equations.
Relevant Equations
Now I know, that because the scalar field is complex it has twice the degrees of freedom so I get two equations of motion (?). They should be given by:
$$\frac{\partial \mathcal{L}}{\partial\varphi}-\partial_\mu\frac{\partial \mathcal{L}}{\partial(\partial_\mu \varphi)}=0$$ and $$\frac{\partial \mathcal{L}}{\partial\varphi^*}-\partial_\mu\frac{\partial \mathcal{L}}{\partial(\partial_\mu \varphi^*)}=0.$$

For the electromagnetic field $A_\mu$ it should just be:
$$\frac{\partial \mathcal{L}}{\partial A_\mu}-\partial_\rho\frac{\partial \mathcal{L}}{\partial(\partial_\rho A_\mu)}=0.$$
Well, I started with the first equation of motion for the scalar field, but I'm really not sure if I'm doing it the right way.

\begin{equation}
\begin{split}
\frac{\partial \mathcal{L}}{\partial \varphi} &= \frac{\partial}{\partial \varphi} [(\partial_\mu \varphi^* - ieA_\mu\varphi^*) (\partial_\mu\varphi+ieA_\mu\varphi)-m^2\varphi^*\varphi-\lambda(\varphi^*\varphi)^2]\\
&= \frac{\partial}{\partial \varphi} [\partial_\mu\varphi^*\partial_\mu\varphi + ieA_\mu\varphi\partial_\mu\varphi^*-ieA_\mu\varphi^*\partial_\mu\varphi+e^2A_\mu\varphi^*\varphi-m^2\varphi^*\varphi-\lambda(\varphi^*\varphi)^2] \\
&= ieA_\mu\partial_\mu\varphi^*+e^2A_\mu\varphi^*-m^2\varphi^*-2\lambda(\varphi^*)^2\varphi
\end{split}
\end{equation}

and

\begin{equation}
\begin{split}
\partial_\mu \frac{\partial \mathcal{L}}{\partial (\partial_\mu \varphi} &= \partial_\mu\frac{\partial}{\partial (\partial_\mu\varphi)}[\partial_\mu\varphi^*\partial_\mu\varphi + ieA_\mu\varphi\partial_\mu\varphi^*-ieA_\mu\varphi^*\partial_\mu\varphi+e^2A_\mu\varphi^*\varphi-m^2\varphi^*\varphi-\lambda(\varphi^*\varphi)^2] \\
&= \partial_\mu [\partial_\mu\varphi^*-ieA_\mu\varphi^*]
\end{split}
\end{equation}

Does this at least go in the right direction? I'm really unsure. Thanks for your help. I appreciate it.
 
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This looks correct, except that the term in the last line of equation (1) proportional to A*phi should be A^2*phi.. The term involving the 4-divergence of the vector potential can be set to zero by adopting a particular gauge.
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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