Equiangularity of a Polar Equation

[daisukekazama]

Homework Statement

Show that the equation below connects the point (r_{0}, \theta_{0}) to the point (r_{1}, \theta_{1}), \theta_{0}\neq\theta_{1}, along a curve that everywhere forms the same angle with the rays \theta=constant.

And here's the equation. I can't get the Latex to work... no clue why.

Homework Equations

N/A.

The Attempt at a Solution

This is part of a larger problem on stereographic projection - I've figured out that this equation, if projected onto a sphere, traces out a loxodrome. I also know that I essentially have to prove that that mess of an equation is a equiangular spiral (logarithmic spiral).

The problem is, no matter how I look at it, I need to calculate the derivative dr/d\theta, which - from where I'm looking - looks like one hell of a messy and convoluted derivative, which I'd rather not do.

Is there an easier, cleaner, more elegant way of solving this problem than brute-forcing the derivative? If not, how do I do the derivative?

 

[Gib Z]

I'm not sure whether you have addressed this part of the question or not, but substitution shows that r indeed connects the given points. I'm not sure of a more elegant way at the moment, but the derivative is much easier to calculate if you extract constants in the way r^(x-b) = r^x/r^b.

Then you are left simply in the form r= C r_0^{t\theta} r_1^{-t\theta} and apply the product rule.

 

[daisukekazama]

Thank you - that helped.