Equilibrium - Ladder against wall

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The discussion revolves around calculating the forces acting on a ladder leaning against a smooth wall. The force exerted by the wall on the ladder is determined to be 129.5N. The friction force is also 129.5N, but the participants are uncertain about how to find the normal force needed to calculate the coefficient of friction. The equilibrium equations for vertical and horizontal forces are referenced, indicating that the normal force from the ground is crucial for further calculations. The conversation highlights the need for clarity on the normal force to solve the problem completely.
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Homework Statement


A 7.0kg ladder is placed against a smooth wall so that it makes an angel of 72deg to the horizontal. A 56kg person stands 4.0m from the bottom of the ladder.

What force does the wall exert on the ladder?
What is the coefficient of friction between the ladder and the ground?

Homework Equations



EFy=0 : Fy=69+540
EFx=0: Fx=Fwall
ET=0: (5.71Fwall)= (69*0.93)+(540 * 1.23)
Fwall=129.5N

Ffriction = uFnormal

The Attempt at a Solution



Force exerted by wall is 129.5N. Friction force is therefore 129.5N

Stuck as to what force is the normal force used to calculate coefficient of friction.
 
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canicon25 said:
EFy=0 : Fy=69+540
What about the force from the floor? (That's the missing normal force.)
 
Thanks
 
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