Equilibrium of a uniform bar inclined at an angle

In summary: A: At A, the rod makes an angle theta with the horizontal (7/24), causing the weight (40 N) to be applied at an angle alpha (3/4) to the horizontal, so that the rod and the bar are in equilibrium.C: The bar and rod are in equilibrium, but if the rod makes an angle theta with the horizontal, where tan theta = 7/24, the bar will be displaced (by x cm) to the right or left.AC: If the rod makes an angle theta with the horizontal, where tan theta = 7/24
  • #36
Solved! Thank you
 

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  • #37
Good !
 
  • #38
Nidum said:
Good !
I know this is from a few months ago, but why do the normal vectors at C and A break up into components?
 
  • #39
I don't think this is right. The normal at A and C don't break up into components and what direction is the normal at A?
 
  • #40
Sorry, mind's a little messed up. nothing's wrong
 
  • #41
OK .
 
  • #42
Well done :)
 

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