1. A uniform bar AB of length 3 m and weight 40 N rests in equilibrium with the lower end A on a smooth plane inclined at an angle alpha to the horizontal, where tan alpha = 3/4 and a point C of the rod against a smooth peg. If the rod makes an angle theta with the horizontal, where tan theta = 7/24, find (a) the magnitudes of the reactions at A and C, (b) the distance AC. 2. Nc (sin 37) + Na = w so Nc (3/5) + Na = 40 Nc (cos 37) = F so Nc (4/5) =F 40 (cos 37)(1.5) = Nc (x) where x is AC so 40 (4/5)(1.5) = Nc (x) so 48 = Nc(x) 3. The first thing I didn't understand was why has the question provided 2 angles at which the plane is inclined to? Secondly, they haven't provided any coefficient of friction or any other variable which would have made solving these equations easier. You need at least one more variable to get any of the required quantities.