Equilibrium of Two People Holding Uniform Beam

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Homework Help Overview

The discussion revolves around the equilibrium of a uniform beam being held by two individuals. The beam is specified to be 7.6 meters long and weighs 450 Newtons, with one person holding it 1 meter from the left end and the other 2 meters from the right end.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to set up equations for force and torque to determine the forces exerted by each person. There is a question regarding the choice of the axis for torque calculations.

Discussion Status

Participants are engaging in a dialogue about the setup of the problem, with some offering reassurance about the choice of axis for torque calculations. There is an acknowledgment that the axis can be placed anywhere, although some suggest that choosing an axis through one of the forces may simplify the calculations.

Contextual Notes

There is an indication of uncertainty regarding the axis selection for torque, which may affect the approach to solving the problem. No additional constraints or rules are mentioned in the discussion.

nameVoid
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two people are holding a unifrom beam of length 7.6m and weight 450N. the first person is holding the beam 1 m from the left end the second is holding the beam 2m from the right end determine the force the each person exerts on the beam.

choosing the axis as the left most person who exerts F1

sum F = F1 + F2 -450=0
sum torque = 4.6F2-2.8*450 =0
 
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hi nameVoid! :wink:

that looks ok :smile: …

what's worrying you about it? :confused:​
 
thanks i was unsure where to take the axis
 
it doesn't matter …

take the axis anywhere (even somewhere really stupid! :biggrin:), and it'll still work :smile:

(though it make the maths easier if you always take the axis through one of the forces, in this case one of the two people or the centre of mass :wink:)
 

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