Equilibrium Separation of HCl with Covalent Bonding: Expert Assistance Needed

[rushil01]

Hey guys, I am currently studying Engieering in Australia and there is one question which was given to us which i have no idea on how to complete and i was wondering if you guys could give me a hand with it;

What is the equilibrium separation of HCl? ITs measured electric dipole moment is 3.60 x 10^-30C.m and the percentage of covalent bonding in HCl is 82.5%

ANy help would be greatly appreciated. Thanx

 

[lightarrow]

Hey guys, I am currently studying Engieering in Australia and there is one question which was given to us which i have no idea on how to complete and i was wondering if you guys could give me a hand with it;

What is the equilibrium separation of HCl? ITs measured electric dipole moment is 3.60 x 10^-30C.m and the percentage of covalent bonding in HCl is 82.5%

ANy help would be greatly appreciated. Thanx

$$r =\ \mu_D/q\cdot P\ =\ 6.25\cdot10^{18}\ \mu_D/P\ =\ <br /> <br /> 6.25\cdot10^{18}\cdot3.6\cdot10^{-30}/0.825\ =\ 2.73\cdot10^{-11}\ m\ =\ 27.3\ pm$$

 

[mate1000]

What are those formulas you came up with and where did 6.25*10^18 come from.
Thanks

 

[rushil01]

i got my lecturer to do it and he used the formula p=qd. I'll post the full working out when i have a little more time