Sinister said:
Yeah, I'm a very visual learner (hence why discrete math isn't my strongest subject), I try to picture a lot of problems and I find that helps me to 1) understand/memorize concepts easily and 2) apply the knowledge in tests.
Then you're in luck, because there's a totally simple visualization of equivalence classes. Just to pick an example, ever see one of those photos of a cow that shows which cuts of meat come from which part of the cow?
Here's a perfect one.
http://bastropcattlecompany.com/catalog/images/cow-anatomy.gif
Now let's define an equivalence class based on this pic. Let's say that our set is the set of cow particles, where a particle is just some tiny part of the cow -- like a molecule, say.
Two cow particles x and y are equivalent if they are in the same section of the cow.
Is this reflexive? Symmetric? Transitive? Yes, yes, and yes, but you should walk through the logic for yourself. Write down the proof that the relation of two cow molecules being in the same numbered section is an equivalence relation.
That's all an equivalence relation is. It's a partition of a set into a collection of mutually disjoint subsets. Every element of the set goes to exactly one subset; and each of the subsets is an equivalence class.
In other words if you have any equivalence relation, and for some element x you defined the
equivalence class of x, denoted [x], as the set of all elements that are equivalent to x; then the set of all the equivalence classes are a partition of the original set.
Another way to say this is that if you have two equivalence classes [a] and
, then either [a] = or [a] and are disjoint. You should prove that.
An equivalence relation gives you a partition; and every partition gives you an equivalence relation. Equivalence classes and partitions are just two ways of looking at the same thing.
Once you get this, equivalence relations are easy. And it's totally visual.
[Note: I think that's a bull, not a cow. Fortunately we're not on the Biology forum]