Equivalent force and couple moment

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SUMMARY

The discussion focuses on calculating the equivalent force and couple moment in a mechanics problem. The user successfully determined the magnitude and angle of the resultant force but struggled with the moment and couple calculations. Using the equation for moment, \(\vec M = \vec r \times \vec F\), the user attempted to find the position vector \(\vec r\) and calculated a moment of 41.58 kN·m, which was later identified as incorrect. Ultimately, the user resolved the issue independently.

PREREQUISITES
  • Understanding of vector cross products
  • Familiarity with force and moment concepts in mechanics
  • Knowledge of coordinate systems in physics
  • Ability to perform calculations involving kN·m units
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  • Review vector cross product calculations in physics
  • Study the principles of moments and couples in mechanics
  • Explore examples of equivalent force systems in engineering
  • Learn about common mistakes in moment calculations and how to avoid them
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Students studying mechanics, engineers working on force analysis, and anyone seeking to understand the principles of moments and couples in physics.

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Homework Statement


I will post a photo of the question in the thread once I've created it. I have found the magnitude and angle of the resultant force, but I am unsure of how to proceed. I find moments and couples confusing.

Homework Equations



$$\vec M = \vec r \times \vec F$$

The Attempt at a Solution



So, to find ##\vec r## I chose a point on ##\vec F## (1, 0.8069) (call it C), and calculated ##r_{BC}##: ##r_{c} = -7i + 0.8069j##. Then I took the cross product of r and F, and got 41.58kN.m, but this is incorrect, and I am stumped.
 
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i found the answer, thanks.
 

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