Equivalent force couple systems at a point on a rigid body

Click For Summary
SUMMARY

The discussion focuses on determining the equivalent force-couple system at point B of a rigid body, specifically a rod subjected to a force P of 250 N at point C. The calculations involve using the moment equation, where the moment about point B is calculated as Mb = 250 N * 0.3 m = 75 Nm in the -k direction. The user expresses confusion regarding the application of two parallel forces at point B and their ability to produce a moment about that point, highlighting a fundamental misunderstanding of force couples and their effects on rigid bodies.

PREREQUISITES
  • Understanding of rigid body mechanics
  • Knowledge of force and moment calculations
  • Familiarity with force couples and their equivalence
  • Ability to interpret and analyze free body diagrams
NEXT STEPS
  • Study the principles of static equilibrium in rigid bodies
  • Learn about the application of force couples in mechanical systems
  • Explore detailed examples of equivalent force-couple systems
  • Review the concept of moments and their calculations in physics
USEFUL FOR

Students in mechanical engineering, physics enthusiasts, and professionals dealing with structural analysis and rigid body dynamics will benefit from this discussion.

reed2100
Messages
49
Reaction score
1

Homework Statement


Attached is a pdf of the assignment problems, I'm looking at problem 1 under the "Try" section. It shows a rod attached to a wall bracket on the left, with a force applied on the right side.

I'm also including a link to the solution, it's under "Problem 3.83" - http://www.academia.edu/9504768/SOLUTION_MANUAL

The force P has a magnitude of 250 N and is applied at the end C of a 500 mm rod AC attached to a bracket. Assuming α = 30° and β = 60°, determine:
a. The equivalent force-couple system acting at point B
b. An equivalent system formed by two parallel forces applied at A and B

(note) - I converted mm to meters first, fyi

Homework Equations


Moment = Force x distance from reference to point of application
Moment = cross product of Force vector and reference-to-PoA vector

The Attempt at a Solution



First I calculated the moment about point B : Mb = F*d = 250 N * .3 m = 75 Nm in -k direction (right hand rule).

Now the question asks me to...substitute?...a force couple at point B in place of force P? If I'm correct, an equivalent force couple is equivalent to another system of force(s) if it has the same effect on the body. So this force couple -at- point B would have to produce the same moment -about- point B. I don't understand that : How can I produce a moment about a point if I apply 2 parallel and equal forces AT that point? If I applied them to point B, wouldn't they just produce arbitrary moments about an infinite number of points down the rod EXCLUDING point B?

I can imagine what a force couple looks like, I've seen diagrams and think I understand the basics of it - but with what I understand I would think I'd have to apply a force some distance from point B, and apply a parallel force of equal magnitude but opposite direction an equal distance on the other side of point B. Kind of like 2 kids pushing around one of those spinning playground things. I can imagine part b) of this question more easily I think.

Does it look like I'm having a misunderstanding of the fundamentals of these concepts, or is the wording strange? Thank you for any/all advice, I appreciate it.
 

Attachments

Physics news on Phys.org
reed2100 said:
If I'm correct, an equivalent force couple is equivalent to another system of force(s) if it has the same effect on the body.

The equivalent force couple would comprise a force and a couple/torque. eg two separate things acting at B.

See..

 

Similar threads

  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K