Equivalent resistance of simple circuit

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SUMMARY

The discussion focuses on finding the equivalent resistance of a complex circuit using Y-Delta transforms. The user initially struggles to identify series and parallel resistors but successfully solves the problem by applying symmetry principles and the Y-Delta transformation method. The symmetry of the circuit allows for the simplification of the network by recognizing equipotential points, ultimately leading to a single equivalent resistance. The Y-Delta transform is highlighted as a reliable technique for reducing complex resistor networks.

PREREQUISITES
  • Understanding of circuit theory, specifically series and parallel resistor configurations.
  • Familiarity with Y-Delta transforms in electrical engineering.
  • Knowledge of symmetry principles in electrical circuits.
  • Basic skills in circuit analysis and simplification techniques.
NEXT STEPS
  • Study the application of Y-Delta transforms in various circuit configurations.
  • Explore advanced circuit analysis techniques, including mesh and nodal analysis.
  • Learn about equipotential surfaces and their implications in circuit design.
  • Investigate other methods for simplifying complex resistor networks, such as Thevenin's and Norton's theorems.
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing and simplifying complex resistor networks.

nil1996
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Homework Statement


Find the equivalent resistance of the following circuit.
http://img706.imageshack.us/img706/9644/zkz7.png


Homework Equations


none


The Attempt at a Solution


I am not able to find out which are resistors are in series and are in parallel.Is there any special method to solve these problems?
 
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Think about drawing this in a different way so you can see the parallel and series resistors more clearly
 
Use the symmetry of the circuit. There is a plane about which the circuit is symmetrical. By symmetry all the points in this plane are equipotential. Armed with this information you can simplify this circuit by removing a resistor as no current flows through it.
 
consciousness said:
Use the symmetry of the circuit. There is a plane about which the circuit is symmetrical. By symmetry all the points in this plane are equipotential. Armed with this information you can simplify this circuit by removing a resistor as no current flows through it.

thanks a lot!:thumbs:
i solved the problem
 
This network is an example of non-parallel/non-serial. The direct method is to use the Y-Delta transforms: http://en.wikipedia.org/wiki/Y-Δ_transform

Then you can slowly reduce the network to a single resistance. The symmetry argument is very clever ... but the transforms work even when you are not feeling clever!
 

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