Equivalent resistance of simple circuit

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Homework Help Overview

The discussion revolves around finding the equivalent resistance of a given circuit, which involves identifying resistors in series and parallel configurations. The subject area is electrical circuits, specifically focusing on resistance calculations.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss methods for identifying series and parallel resistors, with one suggesting a different drawing approach for clarity. Others mention the use of symmetry in the circuit to simplify the analysis and question the effectiveness of this method.

Discussion Status

Some participants have offered guidance on visualizing the circuit differently and utilizing symmetry for simplification. There is acknowledgment of various methods, including Y-Delta transforms, but no explicit consensus on a single approach has been reached.

Contextual Notes

Participants are navigating the complexities of the circuit's configuration, with some expressing uncertainty about the relationships between the resistors. The original poster indicates a lack of prior equations or methods to approach the problem.

nil1996
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Homework Statement


Find the equivalent resistance of the following circuit.
http://img706.imageshack.us/img706/9644/zkz7.png


Homework Equations


none


The Attempt at a Solution


I am not able to find out which are resistors are in series and are in parallel.Is there any special method to solve these problems?
 
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Think about drawing this in a different way so you can see the parallel and series resistors more clearly
 
Use the symmetry of the circuit. There is a plane about which the circuit is symmetrical. By symmetry all the points in this plane are equipotential. Armed with this information you can simplify this circuit by removing a resistor as no current flows through it.
 
consciousness said:
Use the symmetry of the circuit. There is a plane about which the circuit is symmetrical. By symmetry all the points in this plane are equipotential. Armed with this information you can simplify this circuit by removing a resistor as no current flows through it.

thanks a lot!:thumbs:
i solved the problem
 
This network is an example of non-parallel/non-serial. The direct method is to use the Y-Delta transforms: http://en.wikipedia.org/wiki/Y-Δ_transform

Then you can slowly reduce the network to a single resistance. The symmetry argument is very clever ... but the transforms work even when you are not feeling clever!
 

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