- #1

snoble

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Here equivilant means that a sequence in the VS is cauchy under one norm iff it is cauchy under the other norm.

Alright, if you assume the inequality and assume a sequence is Cauchy under one norm then it is easy to show it is Cauchy under the other norm. Just scale the [tex]\epsilon[/tex] appropriately.

Now the other direction is what has me stumped. So assuming that the v.s. norms are equivilant you can get that the norms on the underlying fields are equivilant; just take a sequence in the field that is cauchy under the first norm, multiply the sequence by any non-zero vector - that'll be cauchy in the V.S. under the first norm so cauchy under the second. Then just divide by the value of the vector under the second norm. Then it is clear that the original sequence is Cauchy in the field under the second norm.

I realize that the above is kind of fuzzy but the point is the norms on the underlying field are equivilant. And I know that if two field norms are equivilant then there exists a positive real [tex]\alpha[/tex] such that [tex]\forall k\in F[/tex], [tex]\|k\|_1^\alpha = \|k\|_2 [/tex].

But now I can't seem to get the inequality. I assume it's easiest by trying to show the converse ie if the inequality hold for no constant then you can get a sequence that is Cauchy under one norm but not under the other. But I still can't seem to see it.

Any hope would be appreciated

Thanks,

Steven